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Sflinsj
Originally posted by SFLINSJChuck,
My guy doesn't do -1 RLs. I know someone on here explained how to bet both teams with one laying the -1 1/2 RL to make it essentially a -1 bet. Can you explain how to do this? Thanks buddy.
P.S. It's still early for me so I can't think right now.
Take StL today as an example ML is -155, -1.5 RL is even.
play StL on the ML 155 to win 100
play StL on -1.5 RL 100 to win 100.
Basically you are laying 255 to win 200, or -128 on the -1 RL. If StL wins by 1 you lose the RL play and win the ML play, and you push. The key is your RL wager should equal your ML winnings.
Hope this helps and isn't too confusing.Control what you can control...
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Mi66-What if St. Louis loses? Then you lose both bets, whereas if you are allowed to play St. Louis - 1 run and they lose, you only lose 1 bet. Am I missing something?
I am assuming the bets listed are all 1 unit bets.
ps Sure if St. Louis wins by 2 runs, you win both bets;however. assuming that the intent was to win a one unit bet, I don't see stated method as legitimate.Last edited by savage1; 06-20-2005, 05:22 PM.
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Originally posted by savage1Mi66-What if St. Louis loses? Then you lose both bets, whereas if you are allowed to play St. Louis - 1 run and they lose, you only lose 1 bet. Am I missing something?
I am assuming the bets listed are all 1 unit bets.
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Originally posted by savage1Mi66-What if St. Louis loses? Then you lose both bets, whereas if you are allowed to play St. Louis - 1 run and they lose, you only lose 1 bet. Am I missing something?
I am assuming the bets listed are all 1 unit bets.
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Thanks illjaunt
Originally posted by savage1Mi66-What if St. Louis loses? Then you lose both bets, whereas if you are allowed to play St. Louis - 1 run and they lose, you only lose 1 bet. Am I missing something?
I am assuming the bets listed are all 1 unit bets.
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Originally posted by BigWeinerYes you are missing something, if St. Louis loses, you lose no matter what you played on St. Louis.
The point is that if you bet St.Louis -1 run and they lose, you lose only that bet for 1 unit.
If you play St. Louis on the regular ML and - 1 1/2 runs for 1 unit, you lose two bets if St.Louis loses.
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Originally posted by CashmoneyasiansI think he means to play Cincy at +1.5. Maybe just a typo.Last edited by ChuckLazar; 06-20-2005, 05:29 PM.
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Originally posted by savage1I edited my last post.
The point is that if you bet St.Louis -1 run and they lose, you lose only that bet for 1 unit.
If you play St. Louis on the regular ML and - 1 1/2 runs for 1 unit, you lose two bets if St.Louis loses.
Moneyline $80 to win $50
Runline $50 to win $50
Therefore, $130 to win $100, which is the same thing. Hope that clears is up. Good luck everybody
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Originally posted by savage1Mi66-What if St. Louis loses? Then you lose both bets, whereas if you are allowed to play St. Louis - 1 run and they lose, you only lose 1 bet. Am I missing something?
I am assuming the bets listed are all 1 unit bets.
ps Sure if St. Louis wins by 2 runs, you win both bets;however. assuming that the intent was to win a one unit bet, I don't see stated method as legitimate.Control what you can control...
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Originally posted by BigWeinerIf St. Louis -1 is a one unit play, let's say $130 to win $100, and you don't have pinnicle, but you want to play it, here's how you do it.
Moneyline $80 to win $50
Runline $50 to win $50
Therefore, $130 to win $100, which is the same thing. Hope that clears is up. Good luck everybody
Sorry for the confusion guys. And yes, if StL loses, you lose regardless if you play ML, -1RL, or -1.5 RL.
So just win Cards! and hopefully by a lot!!!Control what you can control...
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Easier way to do that, if you don't us Pinnacle is
You want to bet $500 on this one game, i.e St Louis tonight
Bet:
$250 on -.5 runs at -170 so your risking $425 to win $250
$250 on -1.5 runs at -110 so your risking $275 to win $250
so your $500 now turnes to $700 to win $500 or basically St. Louis -140 -1 run
Hope that helps
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